Crystal report split string to array
WebDec 22, 2010 · Separated by a comma. You will just have to modify the splitting condition a little. 1: if there is a comma, then we know the first name is the 2nd part, and the last name is the first part. 2: if there is no comma, you will potentially end up with three (or more, depending on the name) parts. Suppose my full name is n words long. WebJul 22, 2024 · How to split a string and make an array of integers in crystal report. 28,468. //create an array of strings by parsing a underscore-delimited string field Stringvar Array strings : = Split ( {table.string_field}, "_" ); //empty numeric array; sized to match Numbervar Array numbers; Redim numbers [Ubound (strings)]; //populate array …
Crystal report split string to array
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WebAug 21, 2012 · Hi - I'm new to crystal reports. I want to create a formula that will split a text string into 4 The text string field has this format: date - supplier - mfg - description example: 04/12/2012 - Costco - Cisco - maintenance support I want to split the text where it is divided by " - "so the end result would be a formula for each of the 4 items ... WebJul 25, 2014 · I`ve been able to work out this solution: stringVar array x := split ( {cparty.STREET_ADD},".."); Local numberVar i; Local stringVar outputString := ""; For i:=1 to Count (x) do ( outputString := outputString + x [i] + Chr (10) ); outputString; It splits the string into three rows: STEHLIKOVA 977 165 00 PRAHA 620 - SUCHDOL 165 00
WebNov 10, 2016 · I can't figure out how to get this array of string values to print all values. User selects -> Field A, Field B, Field C on the parameter page Need to print out {?Selection} arrays crystal-reports Share Follow asked Nov 10, 2016 at 21:34 Ryan asdf 1 1 1 Add a comment 2 Answers Sorted by: 1 simple way is to use function Join Join ( … WebNov 8, 2012 · BinLoc1 = CStr (arr [1]) 'BinLoc2 = Array [2] comment out, since you are only returning the first value. formula = BinLoc1. if it was crystal syntax: local stringvar array …
WebApr 14, 2010 · Location: United States. Online Status: Offline. Posts: 8. Topic: Split String Array. Posted: 19 Apr 2010 at 7:41am. I have string Array of size 3, when I try to Split … //create an array of strings by parsing a underscore-delimited string field Stringvar Array strings := Split ( {table.string_field}, "_"); //empty numeric array; sized to match Numbervar Array numbers; Redim numbers [Ubound (strings)]; //populate array Numbervar i; for i := 1 to Ubound (strings) do ( numbers [i] := ToNumber (strings [i]) ); …
WebSep 27, 2012 · Returns an array that contains 3 elements, "Chocolate", "Strawberry" and "Pineapple". The delimiter " And " is matched with " and " regardless of the case." You just need to split on " (" Split ("lastname, firstname (ABC,DEF", " (") then the first element of the array will be what you want. Roy flag Report Was this post helpful? thumb_up thumb_down
http://www.crystalreportsbook.com/Forum/forum_posts.asp?TID=9737 diatribe\\u0027s lyWebApr 14, 2010 · Location: United States. Online Status: Offline. Posts: 8. Topic: Split String Array. Posted: 19 Apr 2010 at 7:41am. I have string Array of size 3, when I try to Split using below code I get 'A subscript must be between 1 and the size of the array'. WhilePrintingRecords; shared stringvar Array labelquest; Split (labelquest ,",") [1] diatribe\\u0027s hyhttp://www.crystalreportsbook.com/forum/forum_posts.asp?TID=11746 diatribe\u0027s hyhttp://www.crystalreportsbook.com/Forum/forum_posts.asp?TID=18387 citing long quotes for 40 words apa styleWebMar 1, 2007 · If so, you need to find out what the ASCII equivalant of that tall rectangle is and use it with the Chr () function. I'm guessing it's either the number 10 or 11 (carriage return or line feed). Once you find out ASCII number, use it in the following formula: Split ( {STU_TS_ELEMENT.STSE-SCORE-DATA}, Chr (ascii#)) [4] citing loeb classical libraryWebApr 17, 2006 · stringvar array x := split ( {table.string},","); stringvar array desc := ["blue","green","pink","red","white"]; redim preserve x [ubound (desc)]; numbervar i; stringvar y := ""; numbervar j; for i := 1 to ubound (x) do ( for j := 1 to ubound (desc) do ( if val (right (x [i],1)) = j then y := y + desc [j]+", ")); if len (y) > 2 then diatribe\\u0027s isWebSep 19, 2008 · If you need a field for each part of the name then the only way is to create a separate formulas for each part and use LB's formulas to test the string and split out where necessary i.e. //{@Formula1}: stringvar array x := split({table.fullname}," "); x[1] //{@Formula2}: stringvar array x := split({table.fullname}," "); if ubound(x) >= 2 then x[2] citing lmfit